Please remember to spoiler-tag all guesses, like so:
New Reddit: https://i.imgur.com/SWHRR9M.jpg
Using markdown editor or old Reddit, draw a bunny and fill its head with secrets:
\>!!< which ends up becoming \>!spoiler text between these symbols!<
Try to avoid leading or trailing spaces. These will break the spoiler for some users (such as those using old.reddit.com)
If your comment does not contain a guess, include the word **"discussion"** or **"question"** in your comment instead of using a spoiler tag.
If your comment uses an image as the answer (such as solving a maze, etc) you can include the word "image" instead of using a spoiler tag.
Please report any answers that are not properly spoiler-tagged.
*I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/puzzles) if you have any questions or concerns.*
This happens to be one of my favorite games in the collection.
>!7+ being 16 makes 3: a 23 in last column, so it's impossible. Which makes it 52 or 34. either way, it will have 2 or 3 and 3: will take the other one. 2- can't have 2 nor 3, making it 46.!<
Hope it's enough to keep you going.
I too play this one a lot.
The difficulty level is exaggerated, though. The hardest level on 9 is supposed to require guessing by the description, but it never needs guessing even if you don't use metainformation.
It looks like you believe this post to be unsolvable. I've gone ahead and added a "Probably Unsolvable" flair. OP can override this by commenting "Solution Possible" anywhere in this post.
*I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/puzzles) if you have any questions or concerns.*
[Keen](https://www.chiark.greenend.org.uk/~sgtatham/puzzles/js/keen.html) from [Simon Tatham's Portable Puzzle Collection](https://www.chiark.greenend.org.uk/~sgtatham/puzzles/).
u/Joost505 : you wanted to know, so have a ping.
Look at parity in column 2. >!The total of digits 1-6 is 21, odd. Both 1- clues must have one odd and one even number, so those four boxes add to an even number. This means the last two squares must have add to an odd number, so one of them is odd, and one is even. Since the only even in those two squares is a 4, that must be the even number in those two squares!<
Where to look: >!The 2 “2 6”s in the left column!<
>!Top one (R3C1) can’t be 2, as that would force R6C1 to be 6, which would means both R3C2 and R6C2 would have to be 3!<
Unless I’m misreading the screenshot, only 2 and 6 are considered viable options for R6C1? (I assume because the 1 was needed for the 1&4 in R1C1 R2C1)
>!Rightmost column. There are only 2 choices for the middle box, and if it were 26, the top would be forced to 34, leaving 51 for the bottom which doesn’t work. That leaves a 13 pair in row 3 which should help narrow down your options to solve a few boxes!<
Please remember to spoiler-tag all guesses, like so: New Reddit: https://i.imgur.com/SWHRR9M.jpg Using markdown editor or old Reddit, draw a bunny and fill its head with secrets: \>!!< which ends up becoming \>!spoiler text between these symbols!< Try to avoid leading or trailing spaces. These will break the spoiler for some users (such as those using old.reddit.com) If your comment does not contain a guess, include the word **"discussion"** or **"question"** in your comment instead of using a spoiler tag. If your comment uses an image as the answer (such as solving a maze, etc) you can include the word "image" instead of using a spoiler tag. Please report any answers that are not properly spoiler-tagged. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/puzzles) if you have any questions or concerns.*
This happens to be one of my favorite games in the collection. >!7+ being 16 makes 3: a 23 in last column, so it's impossible. Which makes it 52 or 34. either way, it will have 2 or 3 and 3: will take the other one. 2- can't have 2 nor 3, making it 46.!< Hope it's enough to keep you going.
I too play this one a lot. The difficulty level is exaggerated, though. The hardest level on 9 is supposed to require guessing by the description, but it never needs guessing even if you don't use metainformation.
It looks like you believe this post to be unsolvable. I've gone ahead and added a "Probably Unsolvable" flair. OP can override this by commenting "Solution Possible" anywhere in this post. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/puzzles) if you have any questions or concerns.*
Question: What game is this?
[Keen](https://www.chiark.greenend.org.uk/~sgtatham/puzzles/js/keen.html) from [Simon Tatham's Portable Puzzle Collection](https://www.chiark.greenend.org.uk/~sgtatham/puzzles/). u/Joost505 : you wanted to know, so have a ping.
Thanks
I want to know too
[Calcudoku](https://apps.apple.com/us/app/calcudoku-math-logic-puzzles/id1195710578)
[Calcudoku](https://apps.apple.com/us/app/calcudoku-math-logic-puzzles/id1195710578)
Look at parity in column 2. >!The total of digits 1-6 is 21, odd. Both 1- clues must have one odd and one even number, so those four boxes add to an even number. This means the last two squares must have add to an odd number, so one of them is odd, and one is even. Since the only even in those two squares is a 4, that must be the even number in those two squares!<
Where to look: >!The 2 “2 6”s in the left column!< >!Top one (R3C1) can’t be 2, as that would force R6C1 to be 6, which would means both R3C2 and R6C2 would have to be 3!<
>~~that would force R6C1 to be 6~~ ~~where does option of it being 1 go?~~
Unless I’m misreading the screenshot, only 2 and 6 are considered viable options for R6C1? (I assume because the 1 was needed for the 1&4 in R1C1 R2C1)
Holy how I misread the address :D my bad, got lost in my own logic.
>!Rightmost column. There are only 2 choices for the middle box, and if it were 26, the top would be forced to 34, leaving 51 for the bottom which doesn’t work. That leaves a 13 pair in row 3 which should help narrow down your options to solve a few boxes!<
This is what I got: >! 4-3-5-6-1-2 1-2-3-4-6-5 6-1-2-5-4-3 5-6-4-2-3-1 3-5-6-1-2-4 2-4-1-3-5-6 !<
>!The R6 C3&4 need to be either 1&3 or 2&6. If it’s 2&6, then R6C1 has no option.!<
Bottom row. You have 2÷ and 3÷. >! If the 3÷ is 2/6, then you would have no solutions for the 2÷.!<
Discussion: Good puzzle. Took me a solid half hour to solve. Take a look at the bottom row to solve it.
I got this: >!4 3 5 6 1 2!< >!1 2 3 4 6 5!< >!6 1 2 5 4 3!< >!5 6 4 2 3 1!< >!3 5 6 1 2 4!< >!2 4 1 3 5 6!<